NEET 2025 Reward Announcement !   *   Join the SATHEE channel for the latest updates- Click Here to Join the Channel.

1- Sets

Latest updates Popular Newest Unanswered Unsolved

F
  • Sticky
How to prepare for Sets for JEE
Answers
2
Views
34
patelrahul
patelrahul
P
How is the answer empty set ?
Answers
2
Views
48
PRB
P
A
Write the following sets in roster form:
Answers
1
Views
544
solution.livedoubt
S
L
In a hostel,25 student take tea ,20 student take coffee,15 student take milk,10 student take both tea and coffee,8 student take both milk and coffee.
Answers
1
Views
53
Math.LiveDoubtClearing
M
M
In a plane, let $A$ be the set of rectangles, $B$ be the set of squares, $C$ be the set of cyclic quadrilaterals and $D$ be the set of isosceles trape
Answers
1
Views
103
Het_1089
H
M
Question: in a survey of 400 student in a school, 100 were listed as taking apple juice, 150 as taking orange juice and and 75 were listed as taking
Answers
1
Views
45
Math.LiveDoubtClearing
M
M
If $A=\{1,3,5,7\}, B=\{2,4,6,8\}$, then $n(P(A \cap B)$ is (1) 0 (2) 8 (3) 1 (4) $2^8$
Answers
1
Views
49
Math.LiveDoubtClearing
M
L
Find the value of $x^2$ for the following values of $x$ :
Answers
1
Views
69
Math.LiveDoubtClearing
M
L
In a hostel,25 student take tea ,20 student take coffee,15 student take milk,10 student take both tea and coffee,8 student take both milk and coffee.
Answers
1
Views
65
Math.LiveDoubtClearing
M
Abhay Pratap Singh
Let A,B and C be sets such that ϕ ≠ A∩B ⊆ C. Then, which of the following statements is not true?
Answers
2
Views
151
Math.LiveDoubtClearing
M
M
Identify a rational number between -5 and 5 . A) 0 B) -7.3 C) -5.7 D) 1.101100110001 ...
Answers
1
Views
60
Math.LiveDoubtClearing
M
A
Number of ordered pair $(\mathrm{A}, \mathrm{B})$ which are subsets of a set containing n elements satisfying the condition $1 \leq n(A)<n(B)$ is
Answers
1
Views
139
Math.LiveDoubtClearing
M
M
Let $\mathrm{S}=\{1,2,3,4\}$. Then the number of elements in the set
Answers
1
Views
101
LiveDoubtClearing
L
You must log in or register to post here.
Back
Top