4-Inverse Trigonometric Functions

Inverse Trigonometric Functions

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How to prepare for Inverse Trigonometric Functions for JEE Mains
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Prayash@iitbombay
Anyone please Solve this question
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Youvraj Singh
\tan^{-1}x + \tan^{-1}y = \frac{1}{2} \sin^{-1} \left[ \frac{2(x+y)(1-xy)}{(1+x^2)(1+y^2)} \right] prove it....
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My solutions are coming wrong..please tell the mistake in my solution
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5
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Sanchi
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Find $x$ from 2 $tan^{-1}(cosx)$ = $tan^{-1}(2cosecx)$
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6
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RJVLKHN
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lonecipher69
The total number of ordered pairs $(x, y)$ satisfying $|y|=\cos x$ and $y=\sin ^{-1}(\sin x)$, where
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3
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sudha
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SUNIT DAS
Let $g(x)=\mathrm{ax}+\mathrm{b}$, where $a<0$ and g is defined from $[1,3]$ onto $[0,2]$ then the value of $\cot (\cos ^{-1}(|\sin x|+|\cos x|)+...$
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Considering only the principal values of inverse trigonometric functions, the number of positive real values of $x$ satisfying
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1
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354
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adarahmittal123bari@gmail
Simplify $\cos ^{-1} x+\cos ^{-1}\left[\frac{x}{2}+\frac{\sqrt{3-3 x^2}}{2}\right] ; \frac{1}{2} \leq x \leq 1$
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2
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Let $y=\sin ^{-1}(\sin 8)-\tan ^{-1}(\tan 10)$. If
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\(y=f(x)=\sin^{-1}\left(\frac{2 x}{1+x^{2}}\right)=\)
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If \( \cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\alpha \), then \( 4 x^{2}-4 x y \cos \alpha+y^{2} \) is equal to
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