d = ut + (1/2)at^2
Where: d = displacement (distance covered)
u = initial velocity (starting from rest, u = 0 m/s)
a = acceleration (2 m/s^2)
t = time interval (1 seconds(5th second))
Let's calculate the distance covered in the 4 seconds:
d = 0 + (1/2) * 2 * (4)^2
d = 0 + (1/2) * 2 * 16
d = 0 + 16 d = 16 meters
and
Let's plug in the values and calculate the distance covered in the 5 seconds:
d = 0 + (1/2) * 2 * (5)^2
d = 0 + (1/2) * 2 * 25
d = 0 + 25 d = 25 meters
The body covers a distance of 25-16=9 meters in the 5th second.
