For the reaction A → B, the rate constant kk was found to obey the relation.......?

[riyasusan]

For the reaction A → B, the rate constant kk was found to obey the relation log⁡k=−2000T+5logk=−T2000+5. What is the activation energy (Ea) of the reaction in kJ/mol?​

(Given: R = 8.314 J/mol·K)

A) 16.6
B) 38.2
C) 76.5
D) 91.2

 

[sudha]

 

[Sneha Duhan]

 

[Abhineet]

 

[RJVLKHN]

We are given the equation:

log k = –2000/T + 5

This is in the form of the Arrhenius equation (logarithmic form):

log k = –Ea / (2.303 × R × T) + constant

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From the given:

• The term –2000/T corresponds to –Ea / (2.303 × R × T)

So we equate:


<br>Ea / (2.303 × R) = 2000<br>

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Step 1: Calculate the denominator:​

• 2.303 × R = 2.303 × 8.314 ≈ 19.15

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Step 2: Multiply:​

• Ea = 2000 × 19.15 ≈ 38,300 joules per mole

Convert to kilojoules:

• Ea ≈ 38.3 kJ/mol

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Let me know if you'd like a shortcut method for solving similar questions.

 

[Amodini]