Find the resultant of two vectors of 50N and 80N acting at a point of an angle of 60°?

anisingh259

New member
Given,
F1=50N
F2=80N
θ= 60º
The resultant of vectors acting on a point using parallelogram law is given by,
R =√ (F12+F22+2F1*F2 cosθ) N
therefore,
R =√ (50+80+2*50*80* cos 60º) N
R = 113.57 N
 
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