Answer: - Let E1 be electric field due to charge 16nc. Let E2 be electric field due to charge 8nc.

E = 1 / 4 П Е (q1 / r²)

The resultant electric field is given by = √ (E1² + E2² + 2.E1.E2.cos Ф

Here E1 - 16 x 10⁴, E2 - 8 x 10⁴, since it is equilateral triangle Ф = 60°

Substituting the values we get,

E = 21.2 x 10⁴

Direction of resultant electric field will be along and away from perpendicular bisector of BC.